Sunday, September 29, 2013
SV#1: Unit F Concept 10 - Finding all real and imaginary zeroes of a polynomial
The first thing we have to do is find our possible zeros, to do this we do the p's and q's and then put our p's over the q's. From there we do Descartes' rule of sign bringing down the signs of each number and then to find the negatives we keep the signs with even degrees the same and the ones with odd degrees change. We see what the change is and then that's how many positive and negative zeros we'll have.
Now we can start doing our synthetic division until our function's highest degree is a square. From there we use the quadratic formula and find our last two zeros. Now we have all of our zeros and we chack if there's four and our highest degree if four so that tells us we have enough.
Tuesday, September 17, 2013
SP#2: Unit E Concept 7 - Graphing a polynomial and identifying all key parts
First we have to take our zeros, since we started with them for this problem, and multiply them in order to get our equitation. Then we look at the highest degree in the equation to find out if its even or odd, in our cases it 4 so its even. Then we look at the coefficient and check if it's positive or negative in our case its +1. This means our end behavior is even positive, which goes towards positive infinity on both ends. To find the zeros we just make our factored equation equal to zero and solve individually. And to find the y-int we just let all the x's in our equation equal zero and we're left with -6.
We plot our zeros and we have to remember that M 1 means that it goes through and M 2 means that it bounces off of the point.We also should remember to plot our y-int and to make sure our end behaviors match with what we decided earlier.
Wednesday, September 11, 2013
WPP#4: Unit E Concept 3 - Maximizing Area
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Tuesday, September 10, 2013
WPP#3: Unit E Concept 2 - Path of Softball
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Monday, September 9, 2013
SP#1: Unit E Concept 1 - Graphing a quadratic and identifying all key parts
First we take our equation and subtract 4. Next we can factor out a 2 and we have to do this to both sides. To find our "square we have to take b and divided it by two and then square it. When we do that we get 16. Then we figure out that x^2 -8x +16 can factor into x-4^2.
From here we can use this to graph and so love. To solve we have to divide by 2 and then take the square root. We have to remember to make it plus and minus.
To graph we Take our vertex which is positive 4 and negative 28. We look at our vertex to find the axis, and we let y equal 0 to find the y-int.
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